2(x^2-12x-4)^1/2-3=15

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Solution for 2(x^2-12x-4)^1/2-3=15 equation: 



2(x^2-12x-4)^1/2-3=15

We move all terms to the left:

2(x^2-12x-4)^1/2-3-(15)=0

We add all the numbers together, and all the variables

2(x^2-12x-4)^1/2-18=0

We multiply all the terms by the denominator


2(x^2-12x-4)^1-18*2=0

We add all the numbers together, and all the variables

2(x^2-12x-4)^1-36=0

We move all terms containing x to the left, all other terms to the right

2(x^2-12x-4)^1=36

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